How to Solve Capacitor Circuits

Identify the circuit., Calculate the total capacitance., Calculate the total charge., Find the charge in each capacitor., Calculate the voltage across each capacitor., Draw and label each capacitor with its charge and voltage.

6 Steps 2 min read Medium

Step-by-Step Guide

  1. Step 1: Identify the circuit.

    A series circuit has only one loop with no branching paths.

    Capacitors in the circuit are arranged in order within the same loop. , Given the voltage and capacitor values for each, find the total capacitance.

    To calculate the total capacitance in a series circuit, use the formula 1CT=1C1+1C2+1C3{\displaystyle {\frac {1}{C_{T}}}={\frac {1}{C_{1}}}+{\frac {1}{C_{2}}}+{\frac {1}{C_{3}}}}.

    For example:
    A series circuit has three different capacitors of value C1 = 2F, C2 = 3F, C3 = 6F.

    Plug in to the formula 1CT=12+13+16{\displaystyle {\frac {1}{C_{T}}}={\frac {1}{2}}+{\frac {1}{3}}+{\frac {1}{6}}} and solve for CT.

    Adding the fraction and taking the inverse, CT = 1F. , The total charge in a circuit depends on the total voltage and the total capacitance in a circuit.

    This relationship is given by the equation Q=CV{\displaystyle Q=CV}.

    For example:
    The circuit has a total capacitance of 1 F and total voltage of 10 V.

    Plug in the given to the equation and solve for Q:
    Q=1∗10=10C{\displaystyle Q=1*10=10C} , For a series circuit, charge across each capacitor is the same and equal to the total charge in the circuit.

    For example:
    The total charge in the circuit is 10 C.

    Then the charge in C1 is 10 C, C2 is 10 C and C1 is 10C. , Rearranging the equation Q=CV{\displaystyle Q=CV} to V=Q/C{\displaystyle V=Q/C}, the voltage across each capacitor can be calculated.

    For Example:
    The charge is 10 C for all capacitors and capacitance values are 2 F, 3 F and 6 F respectively.

    Voltage across first capacitor is V1 = Q1/C1 = 10/2 = 5V Voltage across second capacitor is V2 = Q2/C2 = 10/3 =
    3.3V Voltage across third capacitor is V3 = Q3/C3 = 10/6 =
    1.7 V Note that the sum of individual voltage equals the total voltage in the series circuit. , Once the voltage and charge in each capacitor is calculated, the circuit is solved.

    Label these information in the circuit drawing to keep everything organized. .
  2. Step 2: Calculate the total capacitance.

  3. Step 3: Calculate the total charge.

  4. Step 4: Find the charge in each capacitor.

  5. Step 5: Calculate the voltage across each capacitor.

  6. Step 6: Draw and label each capacitor with its charge and voltage.

Detailed Guide

A series circuit has only one loop with no branching paths.

Capacitors in the circuit are arranged in order within the same loop. , Given the voltage and capacitor values for each, find the total capacitance.

To calculate the total capacitance in a series circuit, use the formula 1CT=1C1+1C2+1C3{\displaystyle {\frac {1}{C_{T}}}={\frac {1}{C_{1}}}+{\frac {1}{C_{2}}}+{\frac {1}{C_{3}}}}.

For example:
A series circuit has three different capacitors of value C1 = 2F, C2 = 3F, C3 = 6F.

Plug in to the formula 1CT=12+13+16{\displaystyle {\frac {1}{C_{T}}}={\frac {1}{2}}+{\frac {1}{3}}+{\frac {1}{6}}} and solve for CT.

Adding the fraction and taking the inverse, CT = 1F. , The total charge in a circuit depends on the total voltage and the total capacitance in a circuit.

This relationship is given by the equation Q=CV{\displaystyle Q=CV}.

For example:
The circuit has a total capacitance of 1 F and total voltage of 10 V.

Plug in the given to the equation and solve for Q:
Q=1∗10=10C{\displaystyle Q=1*10=10C} , For a series circuit, charge across each capacitor is the same and equal to the total charge in the circuit.

For example:
The total charge in the circuit is 10 C.

Then the charge in C1 is 10 C, C2 is 10 C and C1 is 10C. , Rearranging the equation Q=CV{\displaystyle Q=CV} to V=Q/C{\displaystyle V=Q/C}, the voltage across each capacitor can be calculated.

For Example:
The charge is 10 C for all capacitors and capacitance values are 2 F, 3 F and 6 F respectively.

Voltage across first capacitor is V1 = Q1/C1 = 10/2 = 5V Voltage across second capacitor is V2 = Q2/C2 = 10/3 =
3.3V Voltage across third capacitor is V3 = Q3/C3 = 10/6 =
1.7 V Note that the sum of individual voltage equals the total voltage in the series circuit. , Once the voltage and charge in each capacitor is calculated, the circuit is solved.

Label these information in the circuit drawing to keep everything organized. .

About the Author

M

Michael Ellis

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