How to Subnet Using VLSM

List all of your possible subnets., Arrange your requirements in descending order., Assign the appropriate subnet masks to each subnet., Review the Subnetting summary.

4 Steps 1 min read Easy

Step-by-Step Guide

  1. Step 1: List all of your possible subnets.

    /24 = 254 hosts /25 = 126 hosts /26 = 64 hosts /27 = 32 hosts /28 = 16 hosts /29 = 6 hosts /30 = 2 hosts
  2. Step 2: Arrange your requirements in descending order.

    Subnet A
    - 66 Subnet C
    - 22 Subnet B
    - 10 Subnet D
    - 2 , Allocate the First highest subnet Assign
    192.168.10.20 mask /25 for subnet A to satisfy there need for 66 hosts.

    The last octet of the subnet mask will be 1000000 (255.255.255.128) Assign the next highest subnet Assign
    192.168.10.128 the mask /27 for subnet C; the last octet of the subnet mask will be 11100000 (255.255.255.224) Assign the next highest subnet Assign
    192.168.10.160 the mask /28 for subnet B; the last octet of the subnet mask will be 11110000 (255.255.255.240) Assign the last subnet Assign
    192.168.10.176 the mask /30 for subnet D; the last octet of the subnet mask will be 11111100 (255.255.255.252). , Subnet A =
    192.168.10.0/25 ~126 hosts (needed 66) Subnet C =
    192.168.10.128/27 ~ 30 hosts (needed 22) Subnet B =
    192.168.10.160/28 ~ 14 hosts (needed 10) Subnet D =
    192.168.10.176/30 ~ 2 hosts (needed 2)
  3. Step 3: Assign the appropriate subnet masks to each subnet.

  4. Step 4: Review the Subnetting summary.

Detailed Guide

/24 = 254 hosts /25 = 126 hosts /26 = 64 hosts /27 = 32 hosts /28 = 16 hosts /29 = 6 hosts /30 = 2 hosts

Subnet A
- 66 Subnet C
- 22 Subnet B
- 10 Subnet D
- 2 , Allocate the First highest subnet Assign
192.168.10.20 mask /25 for subnet A to satisfy there need for 66 hosts.

The last octet of the subnet mask will be 1000000 (255.255.255.128) Assign the next highest subnet Assign
192.168.10.128 the mask /27 for subnet C; the last octet of the subnet mask will be 11100000 (255.255.255.224) Assign the next highest subnet Assign
192.168.10.160 the mask /28 for subnet B; the last octet of the subnet mask will be 11110000 (255.255.255.240) Assign the last subnet Assign
192.168.10.176 the mask /30 for subnet D; the last octet of the subnet mask will be 11111100 (255.255.255.252). , Subnet A =
192.168.10.0/25 ~126 hosts (needed 66) Subnet C =
192.168.10.128/27 ~ 30 hosts (needed 22) Subnet B =
192.168.10.160/28 ~ 14 hosts (needed 10) Subnet D =
192.168.10.176/30 ~ 2 hosts (needed 2)

About the Author

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Betty Howard

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